C\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 si\u00eau chu\u1ea9n ch\u01b0a bao gi\u1edd thua, chia s\u1ebb t\u1eeb chuy\u00ean gia website c\u1ee7a ch\u00fang t\u00f4i . Chuy\u00ean gia l\u00f4 \u0111\u1ec1 b\u1eadt m\u00ed 7 ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 b\u1ea1ch th\u1ee7 ch\u00ednh x\u00e1c nh\u1ea5t. C\u00e1ch \u0111\u00e1nh l\u00f4 \u0111\u1ec1 v\u1ed1n \u00edt, l\u1ee3i nhu\u1eadn cao. T\u1ec9 l\u1ec7 tr\u00fang b\u1ea3o \u0111\u1ea3m tr\u00ean 70% do website c\u1ee7a ch\u00fang t\u00f4i Vi\u1ec7t Nam th\u1eed nghi\u1ec7m v\u00e0 th\u00e0nh c\u00f4ng.<\/p>\n
C\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 si\u00eau chu\u1ea9n ch\u01b0a bao gi\u1edd thua, chia s\u1ebb t\u1eeb chuy\u00ean gia. Trong b\u00e0i vi\u1ebft n\u00e0y Admin s\u1ebd chia s\u1ebb cho c\u00e1c b\u1ea1n 7 c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 si\u00eau chu\u1ea9n. V\u1edbi s\u1ed1 v\u1ed1n ch\u1ec9 kho\u1ea3ng 2 tri\u1ec7u b\u1ea1n s\u1ebd lu\u00f4n l\u00e3i r\u1ea5t cao n\u1ebfu l\u00e0m \u0111\u00fang h\u01b0\u1edbng d\u1eabn n\u00e0y. B\u1ea1n s\u1eb5n s\u00e0ng ch\u01b0a, c\u00f9ng xem ngay c\u00e1c ph\u01b0\u01a1ng ph\u00e1p si\u00eau vip b\u00ean d\u01b0\u1edbi.<\/p>\n
I. B\u1eaft l\u00f4 khan th\u1ee9 nh\u1ea5t trong c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1<\/h3>\n
T\u00f3m t\u1eaft theo ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u00fang ta s\u1ebd c\u00f3 3 b\u01b0\u1edbc c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
B\u01b0\u1edbc 1: C\u00e1c b\u1ea1n c\u1ea7n chu\u1ea9n b\u1ecb s\u1ed1 ti\u1ec1n v\u1ed1n 2 tri\u1ec7u \u0111\u1ed3ng.<\/p>\n
B\u01b0\u1edbc 2: Th\u1ed1ng k\u00ea kho\u1ea3ng 100 ng\u00e0y.<\/p>\n
B\u01b0\u1edbc 3: Ch\u1ecdn 3 s\u1ed1 khan nh\u1ea5t tr\u00ean 21 ng\u00e0y.<\/p>\n
Nh\u01b0 v\u1eady b\u1ea1n \u0111\u00e3 c\u00f3 3 con l\u00f4 \u0111\u1ec3 \u0111\u00e1nh. Ch\u00fang ta s\u1ebd \u0111\u00e1nh max 4 ng\u00e0y. C\u00e1ch t\u00ednh lo \u0111\u1ec1 si\u00eau chu\u1ea9n n\u00e0y ch\u00fang ta s\u1ebd d\u1ef1a v\u00e0o l\u00f4 khan. C\u00e1ch v\u00e0o ti\u1ec1n nh\u01b0 sau:<\/p>\n
Ng\u00e0y 1: 2 \u0111i\u1ec3m\/con. Ng\u00e0y 2: 5 \u0111i\u1ec3m\/con. Ng\u00e0y 3: 10 \u0111i\u1ec3m\/con. Ng\u00e0y cu\u1ed1i: 30 \u0111i\u1ec3m\/con<\/p>\n
Theo ph\u01b0\u01a1ng ph\u00e1p n\u00e0y, th\u00f4ng th\u01b0\u1eddng ng\u00e0y 1 ho\u1eb7c ng\u00e0y 2, t\u1ed1i \u0111a l\u00e0 ng\u00e0y th\u1ee9 3 b\u1ea1n s\u1ebd tr\u00fang ch\u1eafc ch\u1eafn. H\u00e3y ti\u1ebfp t\u1ee5c theo \u0111\u1ebfn 4 ng\u00e0y. Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y theo v\u00e0 \u0111\u00e1nh d\u00e0i h\u1ea1n, m\u1ed7i th\u00e1ng b\u1ea1n c\u0169ng ki\u1ebfm \u0111\u01b0\u1ee3c kho\u1ea3ng 14 tri\u1ec7u. Nh\u01b0 v\u1eady qu\u00e1 \u1ed5n khi d\u00f9ng ph\u01b0\u01a1ng ph\u00e1p n\u00e0y.<\/p>\n
Ch\u00fa \u00fd: N\u1ebfu trong 3 con, con n\u00e0o \u0111\u00e3 ra khi \u0111\u00e1nh khi b\u1ecf lu\u00f4n con \u0111\u00f3. Ch\u1ea1y l\u1ea1i c\u1ea7u v\u00e0 t\u00ecm c\u1ea7u \u0111\u00e1nh ti\u1ebfp.<\/p>\n
X\u00e1c su\u1ea5t th\u1eafng \u1edf ph\u01b0\u01a1ng ph\u00e1p n\u00e0y l\u00e0 95%.<\/p>\n
II. B\u1eaft l\u00f4 r\u01a1i th\u1ee9 nh\u1ea5t trong c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1<\/h3>\n
<\/p>\n
C\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 si\u00eau chu\u1ea9n th\u1ee9 2 n\u00e0y ch\u00fang ta s\u1ebd s\u1eed d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p l\u00f4 r\u01a1i \u0111\u1ec3 t\u00ecm c\u1ea7u. Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y s\u1ebd ho\u1ea1t \u0111\u1ed9ng c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
B\u01b0\u1edbc 1: Chu\u1ea9n b\u1ecb ti\u1ec1n v\u1ed1n kho\u1ea3ng 2 tri\u1ec7u \u0111\u1ed3ng<\/p>\n
B\u01b0\u1edbc 2: Th\u1ed1ng k\u00ea kho\u1ea3ng 100 ng\u00e0y.<\/p>\n
B\u01b0\u1edbc 3: Ch\u1ecdn 10 con s\u1ed1 r\u01a1i nhi\u1ec1u nh\u1ea5t<\/p>\n
B\u01b0\u1edbc 4: Ch\u1ecdn 3 s\u1ed1 khan nh\u1ea5t trong 10 con kia.<\/p>\n
Sau khi \u0111\u00e3 b\u1eaft l\u00f4 r\u01a1i th\u00e0nh c\u00f4ng \u0111\u01b0\u1ee3c 3 con l\u00f4. C\u00e1c b\u1ea1n \u0111\u00e1nh v\u00e0 v\u00e0o ti\u1ec1n nh\u01b0 sau:<\/p>\n
Ng\u00e0y 1: 2 \u0111i\u1ec3m\/con. Ng\u00e0y 2: 5 \u0111i\u1ec3m\/con. Ng\u00e0y 3: 10 \u0111i\u1ec3m\/con. Ng\u00e0y 4: 30 \u0111i\u1ec3m\/con.<\/p>\n
Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u00fang ta c\u0169ng ch\u1ec9 s\u1eed d\u1ee5ng trong max 4 ng\u00e0y. N\u1ebfu con n\u00e0o ra, b\u1ecf lu\u00f4n con \u0111\u00f3 v\u00e0 th\u1ed1ng k\u00ea t\u00ecm c\u1ea7u \u0111\u00e1nh ti\u1ebfp.<\/p>\n
T\u1ec9 l\u1ec7 th\u1eafng \u1edf ph\u01b0\u01a1ng ph\u00e1p n\u00e0y l\u00e0 95%.<\/p>\n
III. B\u1eaft l\u00f4 r\u01a1i th\u1ee9 2 trong c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1<\/h3>\n
C\u00e1ch t\u00ednh n\u00e0y t\u01b0\u01a1ng t\u1ef1 nh\u01b0 c\u00e1ch s\u1ed1 2 trong c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 si\u00eau chu\u1ea9n. Ch\u00fang ta s\u1ebd s\u1eed d\u1ee5ng l\u00f4 r\u01a1i th\u1ee9 2 \u0111\u1ec3 \u0111\u00e1nh.<\/p>\n
B\u01b0\u1edbc 1: S\u1ed1 v\u1ed1n c\u1ea7n c\u00f3 l\u00e0 2 tri\u1ec7u<\/p>\n
B\u01b0\u1edbc 2: Th\u1ed1ng k\u00ea trong kho\u1ea3ng 100 ng\u00e0y<\/p>\n
B\u01b0\u1edbc 3: L\u1ef1a ch\u1ecdn 10 con s\u1ed1 r\u01a1i nhi\u1ec1u nh\u1ea5t<\/p>\n
B\u01b0\u1edbc 4: Ch\u1ecdn 3 con r\u01a1i nhi\u1ec1u nh\u1ea5t trong 10 con.<\/p>\n
Nh\u01b0 v\u1eady \u1edf c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 si\u00eau chu\u1ea9n n\u00e0y ch\u00fang ta c\u0169ng s\u1ebd c\u00f3 3 con s\u1ed1 \u0111\u1ec3 \u0111\u00e1nh l\u00f4. C\u00e1ch v\u00e0o ti\u1ec1n c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
Ng\u00e0y 1: 2 \u0111i\u1ec3m\/con. Ng\u00e0y 2: 5 \u0111i\u1ec3m\/con. Ng\u00e0y 3: 10 \u0111i\u1ec3m\/con. Ng\u00e0y 4: 30 \u0111i\u1ec3m\/con.<\/p>\n
Sau khi con n\u00e0o \u0111\u00e3 ra, c\u00e1c b\u1ea1n b\u1ecf lu\u00f4n con \u0111\u00f3 v\u00e0 l\u00e0m l\u1ea1i t\u1eeb b\u01b0\u1edbc 1 \u0111\u1ec3 t\u00ecm c\u1ea7u \u0111\u00e1nh ti\u1ebfp.<\/p>\n
T\u1ec9 l\u1ec7 th\u1eafng \u1edf ph\u01b0\u01a1ng ph\u00e1p n\u00e0y l\u00ean \u0111\u1ebfn 95%.<\/p>\n
IV. B\u1eaft l\u00f4 khan th\u1ee9 2 trong c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1<\/h3>\n
<\/p>\n
Ph\u1ea7n 4 n\u00e0y ch\u00fang ta s\u1ebd \u00e1p d\u1ee5ng nh\u01b0 ph\u01b0\u01a1ng ph\u00e1p th\u1ee9 nh\u1ea5t. Nh\u01b0ng c\u00e1ch th\u1ed1ng k\u00ea v\u00e0 c\u00e1ch \u0111\u00e1nh c\u00f3 kh\u00e1c nhau. C\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 si\u00eau chu\u1ea9n n\u00e0y tuy m\u1ea1o hi\u1ec3m nh\u01b0ng t\u1ec9 l\u1ec7 chi\u1ebfn th\u1eafng v\u1eabn r\u1ea5t t\u1ed1t.<\/p>\n
B\u01b0\u1edbc 1: Chu\u1ea9n b\u1ecb ti\u1ec1n v\u1ed1n l\u00e0 2 tri\u1ec7u<\/p>\n
B\u01b0\u1edbc 2: Th\u1ed1ng k\u00ea trong kho\u1ea3ng 100 ng\u00e0y<\/p>\n
B\u01b0\u1edbc 3: L\u1ef1a ch\u1ecdn 3 con s\u1ed1 c\u00f3 t\u1ec9 l\u1ec7 khan nhi\u1ec1u nh\u1ea5t<\/p>\n
B\u01b0\u1edbc 4: Ch\u1ecdn 1 s\u1ed1 khan cao nh\u1ea5t trong 3 con \u0111\u00f3.<\/p>\n
Nh\u01b0 v\u1eady \u1edf c\u00e1ch t\u00ednh n\u00e0y ch\u00fang ta ch\u1ec9 s\u1eed d\u1ee5ng duy nh\u1ea5t m\u1ed9t c\u1eb7p s\u1ed1. V\u00e0 ch\u00fang ta s\u1ebd \u0111\u00e1nh max 9 ng\u00e0y cho ph\u01b0\u01a1ng ph\u00e1p n\u00e0y. C\u1ee5 th\u1ec3 c\u00e1ch v\u00e0o ti\u1ec1n nh\u01b0 sau.<\/p>\n
Ng\u00e0y 1: 2 \u0111i\u1ec3m. Ng\u00e0y 2: 5 \u0111i\u1ec3m. Ng\u00e0y 3: 10 \u0111i\u1ec3m. Ng\u00e0y 4: 10 \u0111i\u1ec3m. Ng\u00e0y 5: 15 \u0111i\u1ec3m. Ng\u00e0y 6: 20 \u0111i\u1ec3m. Ng\u00e0y 7: 25 \u0111i\u1ec3m. Ng\u00e0y 8: 30 \u0111i\u1ec3m. Ng\u00e0y th\u1ee9 9 c\u00f2n bao nhi\u1ec1u ti\u1ec1n \u0111\u00e1nh h\u1ebft.<\/p>\n
Sau khi s\u1ed1 \u0111\u00e3 ra, th\u01b0\u1eddng th\u00ec ng\u00e0y 2 \u0111\u1ebfn ng\u00e0y 4 s\u1ebd ra. B\u1ea1n b\u1ecf kh\u00f4ng \u0111\u00e1nh n\u1eefa v\u00e0 th\u1ed1ng k\u00ea l\u1ea1i t\u1eeb \u0111\u1ea7u.<\/p>\n
T\u1ec9 l\u1ec7 th\u1eafng \u1edf ph\u01b0\u01a1ng ph\u00e1p n\u00e0y l\u00e0 89%.<\/p>\n
V. B\u1eaft l\u00f4 \u1ed5n \u0111\u1ecbnh trong c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1<\/h3>\n
\u1ede c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 si\u00eau chu\u1ea9n th\u1ee9 5 n\u00e0y ch\u00fang ta c\u0169ng s\u1ebd ch\u1ec9 soi c\u1ea7u l\u1ea5y 1 c\u1eb7p s\u1ed1 duy nh\u1ea5t. Ch\u00fang ta s\u1ebd nu\u00f4i c\u1eb7p s\u1ed1 n\u00e0y trong max 9 ng\u00e0y.<\/p>\n
B\u01b0\u1edbc 1: Chu\u1ea9n b\u1ecb 2 tri\u1ec7u ti\u1ec1n v\u1ed1n<\/p>\n
B\u01b0\u1edbc 2: Th\u1ed1ng k\u00ea trong kho\u1ea3ng 100 ng\u00e0y \u1edf \u0111\u00e0i mu\u1ed1n \u0111\u00e1nh<\/p>\n
B\u01b0\u1edbc 3: L\u1ef1a ch\u1ecdn c\u1eb7p s\u1ed1 c\u00f3 chu k\u1ef3 \u1ed5n \u0111\u1ecbnh nh\u1ea5t.<\/p>\n
B\u01b0\u1edbc 4: Ki\u1ec3m tra l\u1ea1i \u0111\u1ec3 xem con s\u1ed1 n\u00e0y \u0111\u00e3 ra c\u00e1ch \u0111\u00e2y 4 \u0111\u1ebfn 6 ng\u00e0y ch\u01b0a.<\/p>\n
N\u1ebfu \u0111\u00fang theo y\u00eau c\u1ea7u b\u00ean tr\u00ean. Ch\u00fang ta s\u1ebd s\u1eed d\u1ee5ng con s\u1ed1 n\u00e0y \u0111\u1ec3 b\u1eaft \u0111\u1ea7u v\u00e0o ti\u1ec1n nh\u01b0 sau:<\/p>\n
Ng\u00e0y 1: 2 \u0111i\u1ec3m. Ng\u00e0y 2: 5 \u0111i\u1ec3m. Ng\u00e0y 3: 10 \u0111i\u1ec3m. Ng\u00e0y 4: 10 \u0111i\u1ec3m. Ng\u00e0y 5: 15 \u0111i\u1ec3m. Ng\u00e0y 6: 20 \u0111i\u1ec3m. Ng\u00e0y 7: 25 \u0111i\u1ec3m. Ng\u00e0y 8: 30 \u0111i\u1ec3m. Ng\u00e0y th\u1ee9 9 c\u00f2n bao nhi\u1ec1u ti\u1ec1n \u0111\u00e1nh h\u1ebft.<\/p>\n
Khi \u0111\u00e1nh, n\u1ebfu s\u1ed1 ra \u1edf b\u1ea5t k\u1ef3 ng\u00e0y n\u00e0o th\u00ec d\u1eebng l\u1ea1i kh\u00f4ng \u0111\u00e1nh n\u1eefa. Sau \u0111\u00f3 ph\u00e2n t\u00edch th\u1ed1ng k\u00ea l\u1ea1i t\u1eeb \u0111\u1ea7u \u0111\u1ec3 t\u00ecm c\u1ea7u \u0111\u00e1nh ti\u1ebfp.<\/p>\n
T\u1ec9 l\u1ec7 th\u1eafng \u1edf ph\u01b0\u01a1ng ph\u00e1p n\u00e0y l\u00e0 89%.<\/p>\n
<\/p>\n
VI. B\u1eaft l\u00f4 m\u00e9 khan trong c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1<\/h3>\n
\u1ede ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u00fang ta s\u1ebd c\u1ea7n ph\u1ea3i d\u1ef1 \u0111o\u00e1n \u0111\u01b0\u1ee3c con l\u00f4 n\u00e0o s\u1ebd c\u00f3 kh\u1ea3 n\u0103ng khan trong t\u01b0\u01a1ng lai. Ch\u00fang ta s\u1ebd \u0111\u00e1nh tr\u01b0\u1edbc khi n\u00f3 khan.<\/p>\n
B\u01b0\u1edbc 1: Chu\u1ea9n b\u1ecb v\u1ed1n l\u00e0 2 tri\u1ec7u \u0111\u1ed3ng<\/p>\n
B\u01b0\u1edbc 2: Th\u1ed1ng k\u00ea trong kho\u1ea3ng 100 ng\u00e0y.<\/p>\n
B\u01b0\u1edbc 3: L\u1ef1a ch\u1ecdn ph\u00e2n t\u00edch 1 con s\u1ed1 c\u00f3 kh\u1ea3 n\u0103ng khan<\/p>\n
B\u01b0\u1edbc 4: Ch\u1ecdn 1 trong 2 con g\u1ea7n s\u00e1t con khan. Sau \u0111\u00f3 c\u1ea7n ki\u1ec3m tra l\u1ea1i \u0111\u1ec3 xem con n\u00e0y \u0111\u00e3 ra c\u00e1ch \u0111\u00f3 4-6 ng\u00e0y.<\/p>\n
Sau \u0111\u00f3 ch\u00fang ta s\u1ebd c\u00f3 duy nh\u1ea5t 1 con s\u1ed1. \u1ede c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 si\u00eau chu\u1ea9n n\u00e0y ch\u00fang ta s\u1ebd nu\u00f4i trong max 9 ng\u00e0y c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
Ng\u00e0y 1: 2 \u0111i\u1ec3m. Ng\u00e0y 2: 5 \u0111i\u1ec3m. Ng\u00e0y 3: 10 \u0111i\u1ec3m. Ng\u00e0y 4: 10 \u0111i\u1ec3m. Ng\u00e0y 5: 15 \u0111i\u1ec3m. Ng\u00e0y 6: 20 \u0111i\u1ec3m. Ng\u00e0y 7: 25 \u0111i\u1ec3m. Ng\u00e0y 8: 30 \u0111i\u1ec3m. Ng\u00e0y th\u1ee9 9 c\u00f2n bao nhi\u1ec1u ti\u1ec1n \u0111\u00e1nh h\u1ebft.<\/p>\n
Khi \u0111\u00e1nh, s\u1ed1 ra \u1edf b\u1ea5t k\u1ef3 ng\u00e0y n\u00e0o th\u00ec b\u1ea1n ph\u1ea3i d\u1eebng l\u1ea1i kh\u00f4ng \u0111\u00e1nh n\u1eefa. Ti\u1ebfp t\u1ee5c l\u00e0m l\u1ea1i t\u1eeb \u0111\u1ea7u \u0111\u1ec3 soi c\u1ea7u c\u1ea7n \u0111\u00e1nh.<\/p>\n
T\u1ec9 l\u1ec7 th\u1eafng \u1edf ph\u01b0\u01a1ng ph\u00e1p n\u00e0y l\u00e0 92%.<\/p>\n
VII. B\u1eaft l\u00f4 ng\u1eabu nhi\u00ean trong c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1<\/h3>\n
Ph\u01b0\u01a1ng ph\u00e1p cu\u1ed1i c\u00f9ng trong c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 si\u00eau chu\u1ea9n. Ch\u00fang ta s\u1ebd d\u1ef1a v\u00e0o t\u00e2m l\u00fd \u0111\u1ec3 b\u1eaft c\u1ea7u. \u0110\u00e2y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 m\u1ea1o hi\u1ec3m nh\u1ea5t hi\u1ec7n nay. N\u00f3 kh\u00f4ng theo quy tr\u00ecnh hay c\u00e1ch t\u00ednh n\u00e0o c\u1ea3. N\u00f3 ph\u1ee5 thu\u1ed9c v\u00e0o ch\u00ednh b\u1ea1n.<\/p>\n
B\u01b0\u1edbc 1: Chu\u1ea9n b\u1ecb 2 tri\u1ec7u ti\u1ec1n v\u1ed1n \u0111\u1ec3 ch\u01a1i<\/p>\n
B\u01b0\u1edbc 2: Ch\u1ecdn duy nh\u1ea5t 1 s\u1ed1 ng\u1eabu nhi\u00ean m\u00e0 b\u1ea1n k\u1ebft nh\u1ea5t<\/p>\n
Ch\u00fang ta ch\u1ec9 c\u00f3 2 b\u01b0\u1edbc v\u00ec \u0111\u00e2y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p c\u1ee7a b\u1ea1n. S\u1ed1 b\u1ea1n th\u00edch th\u00ec b\u1ea1n \u0111\u00e1nh m\u00e0 kh\u00f4ng c\u1ea7n l\u00e0m theo quy tr\u00ecnh n\u00e0o c\u1ea3. Nh\u01b0ng b\u1ea1n v\u1eabn ph\u1ea3i v\u00e0o ti\u1ec1n theo c\u00e1ch t\u00ednh c\u1ee7a admin. V\u00ec \u0111\u00e2y l\u00e0 c\u00e1ch v\u00e0o ti\u1ec1n an to\u00e0n nh\u1ea5t. C\u00e1ch v\u00e0o ti\u1ec1n n\u00e0y, n\u1ebfu b\u1ea1n th\u1eafng \u1edf b\u1ea5t k\u1ef3 ng\u00e0y n\u00e0o c\u0169ng s\u1ebd c\u00f3 l\u00e3i.<\/p>\n
Ng\u00e0y 1: 2 \u0111i\u1ec3m. Ng\u00e0y 2: 5 \u0111i\u1ec3m. Ng\u00e0y 3: 10 \u0111i\u1ec3m. Ng\u00e0y 4: 10 \u0111i\u1ec3m. Ng\u00e0y 5: 15 \u0111i\u1ec3m. Ng\u00e0y 6: 20 \u0111i\u1ec3m. Ng\u00e0y 7: 25 \u0111i\u1ec3m. Ng\u00e0y 8: 30 \u0111i\u1ec3m. Ng\u00e0y th\u1ee9 9 c\u00f2n bao nhi\u1ec1u ti\u1ec1n \u0111\u00e1nh h\u1ebft.<\/p>\n
Sau khi \u0111\u00e1nh m\u00e0 s\u1ed1 ra \u1edf b\u1ea5t c\u1ee9 ng\u00e0y n\u00e0o c\u0169ng n\u00ean d\u1eebng l\u1ea1i. Sau \u0111\u00f3 l\u00e0m l\u1ea1i t\u1eeb b\u01b0\u1edbc 1.<\/p>\n
X\u00e1c su\u1ea5t th\u1eafng \u1edf c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 n\u00e0y l\u00e0: 70%.<\/p>\n
L\u01b0u \u00fd: \u1edf ph\u01b0\u01a1ng ph\u00e1p n\u00e0y, n\u1ebfu b\u1ea1n l\u00e0 ng\u01b0\u1eddi c\u00f3 kh\u1ea3 n\u0103ng t\u01b0 duy v\u00e0 c\u1ea3m nh\u1eadn t\u1ed1t v\u1ec1 c\u00e1c con s\u1ed1. B\u1ea1n s\u1ebd d\u1ec5 d\u00e0ng chi\u1ebfn th\u1eafng.<\/p>\n
K\u1ebft Th\u00fac<\/h3>\n
B\u00ean tr\u00ean l\u00e0 7 kinh nghi\u1ec7m trong c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 si\u00eau chu\u1ea9n do admin \u0111\u00fac k\u1ebft trong nhi\u1ec1u n\u0103m qua. C\u00e1c ph\u01b0\u01a1ng ph\u00e1p n\u00e0y hi\u1ec7n t\u1ea1i \u0111ang \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng chung v\u1edbi c\u00e1c ph\u01b0\u01a1ng ph\u00e1p kh\u00e1c \u0111\u1ec3 soi c\u1ea7u xsmb v\u00e0 c\u00e1c mi\u1ec1n kh\u00e1c h\u00e0ng ng\u00e0y.<\/p>\n
Ch\u00fang t\u00f4i kh\u00f4ng b\u1ea3o \u0111\u1ea3m 100% c\u00e1c b\u1ea1n s\u1ebd th\u1eafng nh\u01b0ng b\u1ea3o \u0111\u1ea3m r\u1eb1ng b\u1ea1n s\u1ebd kh\u00f4ng bao gi\u1edd b\u1ecb l\u1ed7 khi \u0111\u00e1nh theo 7 ph\u01b0\u01a1ng ph\u00e1p b\u00ean tr\u00ean. B\u1edfi c\u00e1c ph\u01b0\u01a1ng ph\u00e1p n\u00e0y \u0111\u00e3 \u0111\u01b0\u1ee3c th\u1eed nghi\u1ec7m tr\u00ean h\u01a1n 5 th\u00e1ng tr\u01b0\u1edbc khi chia s\u1ebb.<\/p>\n<\/div>\n<\/div>\n<\/div>\n